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2 years ago

12

Help anyone know this??

1 answer:

djverab [1.8K]2 years ago

3 0

Answer:

plug n and r into the equation for the answers.

Step-by-step explanation:

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Pamela's age is two times Jiri's age. The sum of their ages is <br> 33<br> . What is Jiri's age?

notka56 [123]

Let x is Jiri's age
2x is Pamela's age

x + 2x = 33
3x =33
x = 33/3
x =11
Answer: Jiri's age is 11

4 0

2 years ago

Read 2 more answers

Оо<br> О<br> ср А<br> Divide:<br> 5/8 divided by 3/4

Angelina_Jolie [31]

Answer:

solution

5/8 ÷3/4

=5÷3=1.6666666667

=4÷8=2

=1<u>1</u>

<u> </u><u> </u><u> </u>2

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2 years ago

(please help me)

Jobisdone [24]

Answer:

8/14

Step-by-step explanation:

there are 5 odd numbers and 3 numbers are coloured red

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1 year ago

Find angle A and angle B..

ExtremeBDS [4]

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

$\tt{\angle{c}=110°}$

and,

$\tt{BC=AC}$

⠀⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆Find the $\angle{B} ~and~\angle{A}$

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Here,

BC =AC

so,

⠀⠀⠀

$\angle{A}=\angle{B}$

we know that,

$\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}$

But $\angle{C}=110°$ (Ģìvéñ)

so..

$\angle{A}+\angle{B}+110°=180°$

$\angle{A}+\angle{A}+110°=180°$

$\because{\angle{A}=\angle{B} }$

$2\angle{A}=180°-110°$

$2\angle{A}=70°$

$\angle{A}=\dfrac{70°}{2}$

$\boxed{\orange{\angle{A}=35°}}$

But...

$\angle{A}=\angle{B}$

soo,

$\boxed{\orange{\angle{B}=35°}}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

⠀⠀⠀⠀

$\boxed{\green{\angle{A}=35°}}$

$\boxed{\green{\angle{B}=35°}}$

7 0

2 years ago

In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while

I am Lyosha [343]

Answer:

See Below.

Step-by-step explanation:

We are given that:

$\angle ABC \cong \angle DEC\text{ and } \angle GFE \cong \angle DCE$

By vertical angles:

$\displaystyle \angle DEC\cong \angle GEF\text{ and } \angle DCE\cong \angle ACB$

Hence, by substitution:

$\displaystyle \angle ABC\cong \angle GEF\text{ and } \angle GFE\cong \angle ACB$

Then by Angle-Angle Similarity:

$\Delta ABC \sim \Delta GEF$

8 0

2 years ago