Answer:
5
Step-by-step explanation:
5
Answer:
A. 4
B. 1
Step-by-step explanation:
The degree of a one-variable polynomial is the largest exponent of the variable.
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<h3>A.</h3>
For f(x) = x^4 -3x^2 +2 and g(x) = 2x^4 -6x^2 +2x -1, the sum f(x) +a·g(x) will be ...
(x^4 -3x^2 +2) +a(2x^4 -6x^2 +2x -1)
= (1 +2a)x^4 +(-3-6a)x^2 +2ax -a
The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.
The largest possible degree of f+ag is 4.
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<h3>B.</h3>
The polynomial sum is ...
f+bg = (1 +2b)x^4 +(-3-6b)x^2 +2bx -b
When b = -1/2, the first two terms disappear and the sum becomes ...
f+bg = -x +1/2 . . . . . . a polynomial of degree 1
The smallest possible degree of f+bg is 1.
Answer:
25
Explanation:
In order to solve this the easiest way you can use equivalent fractions.

Since 4 times 5 equals 20 we can multiply 5 times 5 to get our answer.

25 is the answer. But, if we couldn't have gotten to 20 through the multiplication we could use a proportion. That would look like the initial problem but instead of a "?" we would use a variable. I will use <em>t</em> for total.

So now we have our problem set up. The next step is to cross multiply. 4 by <em>t</em> and 5 by 20.

And now we can solve it like a normal algebra problem.

Either way, we get 25.
OT = 4
PT = 6.93
<u>Explanation :</u>
<u />
OS = OT = R = 4
Hence ∠OTS = ∠OST, (Angles opposite to equal sides are equal)
∠TOS + ∠OTS + ∠OST = 180°
60° + ∠OTS + ∠OST = 180°
2∠OTS = 180° - 60° (∠OTS = ∠OST)
Hence, ∠TOS = ∠OTS = ∠OST = 60°
Hence, ΔOST is an equilateral triangle,
Therefore, OS = OT = ST = 4
Let us draw a perpendicular from OD on PT.
ΔODT is a right angled triangle
∠DTO = 90° - ∠OTS = 30° (Angle of a rectangle is 90°)
in ΔDTO,
cos 30° = DT/OT
DT =
= 3.46
PT = 2*DT = 6.93