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BabaBlast [244]

3 years ago

6

Please help me asap !!!!!

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

would decrease i believe

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Water flows in a horizontal pipe of length L. At the midpoint L/2, the pipe diameter changes. On one side of the midpoint, the p

andrew-mc [135]

Answer:

4cm

Explanation:

Hello!

To solve this problem use the following steps, the procedure is attached.

1. draw the complete outline of the problem

2. Use the continuation equation that states that the volumetric flow at the inlet of the pipe is the same as it should come out, remember that the flow is the product of the cross-sectional area by the flow rate, finally use algebra and input data to Find the exit diameter.

8 0

3 years ago

The work function for silver is 4.73 eV. (a) Convert the value of the work function from electron volts to joules.

pogonyaev

Answer:

$W=7.56\times 10^{-19}\ J$

Explanation:

Given that,

The work function for silver is 4.73 eV.

We need to find the value of the work function from electron volts to joules.

We know that,

$1\ eV=1.6\times 10^{-19}\ J$

For 4.73 eV,

$4.73\ eV=1.6\times 10^{-19}\times 4.73\\\\=7.56\times 10^{-19}\ J$

So, the work function for silver is $7.56\times 10^{-19}\ J$ .

6 0

3 years ago

An object at rest has equal forces acting on it. This can be described as a(n) _____________ force.

san4es73 [151]

Answer. Balanced
Explanation. Balanced forces provides an equal reaction to each action. For example, if you push on a wall, your hand isn’t going to go through. This is because the push is equal to the pull and the forces are balanced.
Hope this helped, let me know if it’s correct so others can use it :)
Good luck

4 0

3 years ago

Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates fo

eduard

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at

using equation (1):

<u>Vf₂ = 2 Vf₁</u>

<u>It shows that final speed of Joe is twice the final speed of Jim.</u>

3 0

3 years ago

School homework about multiplying fractions <br><br>worth 30 brainly points

RoseWind [281]

Answer:

Explanation:

1. $\frac{1}{3}$ x $\frac{6}{7}$ = $\frac{6}{21}$

= $\frac{2}{7}$

b. $\frac{6}{8}$ + $\frac{4}{9}$ = $\frac{24}{72}$

= $\frac{1}{3}$

c. $\frac{10}{15}$ x $\frac{3}{4}$ = $\frac{30}{60}$

= $\frac{1}{2}$

d. $\frac{7}{10}$ of $\frac{5}{10}$ = $\frac{7}{10}$ x $\frac{5}{10}$

= $\frac{35}{100}$

= $\frac{7}{20}$

e. $\frac{3}{8}$ of $\frac{4}{6}$ = $\frac{3}{8}$ x $\frac{4}{6}$

= $\frac{12}{48}$

= $\frac{1}{4}$

f. $\frac{7}{12}$ of $\frac{9}{14}$ = $\frac{7}{12}$ x $\frac{9}{14}$

= $\frac{63}{168}$

= $\frac{3}{8}$

2. $\frac{22}{6}$ x $\frac{3}{11}$ = $\frac{66}{66}$

= 1

b. $\frac{15}{6}$ x $\frac{4}{5}$ = $\frac{60}{30}$

= 2

c. $\frac{25}{8}$ x $\frac{4}{10}$ = $\frac{100}{80}$

= $\frac{5}{4}$

d. $\frac{33}{12}$ x $\frac{4}{15}$ = $\frac{132}{180}$

= $\frac{11}{15}$

4 0

3 years ago