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iris [78.8K]
3 years ago
15

Ed Parker joined a health club. There was a $49 registration fee, and a $17.50 monthly fee. If Ed visits the club 2 times a week

for a year, what does each workout cost him?
Mathematics
2 answers:
frez [133]3 years ago
8 0

Answer:

The cost of each workout is $ 2.49

Step-by-step explanation:

Given :  Ed Parker joined a health club. There was a $49 registration fee, and a $17.50 monthly fee.

also, Ed visits the club 2 times a week for a year.

We have to calculate the cost of each workout.

We first find the cost that Ed Parker paid to joined a health club

Since, There was a $49 registration fee, and a $17.50 monthly fee.

For a year ,

We have 12 months

So total cost = 49 + 17.50(12) = $ 259

1 year has 52 weeks.

Thus, the weekly fee is  \frac{259}{52}=4.98

Since, he visits the club 2 times a week

Thus, each workout cost him \frac{4.98}{2}=2.49

Thus, the cost of each workout is $ 2.49

Allushta [10]3 years ago
6 0
He should would have to pay 298.
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A rental truck costs $96 per day plus $0.60 per each mile. If Calvin can spend a maximum of $120, how many miles can he drive th
nikdorinn [45]

Answer:

40 miles

Step-by-step explanation:

You would have to start by doing $120 - $96 for the per-day fee, which leaves Calvin with $24 to spend on miles.

Next you would do $24 ÷ $0.60 to find the number of miles he can drive, which is 40 miles.

5 0
3 years ago
HELPPPPP PLEASEEEE!!!!!Find the Area of the Rectangle:
tangare [24]

Answer:

62

Step-by-step explanation:

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7 0
3 years ago
Help please<3 for all questions with solutions plz
antiseptic1488 [7]

Answer:

a) h = -\frac{7}{4}, b)  h = f\,\circ\,g (-5) = \frac{3}{2}, c) h = g\,\circ\,f (-2) = \frac{3}{8}

Step-by-step explanation:

We proceed to solve each exercise below:

a) f(-2) +3\cdot g(0)

h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)

h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)

h = -4+\frac{9}{4}

h = \frac{-16+9}{4}

h = -\frac{7}{4}

b) h = f\,\circ \,g (-5)

h = f\,\circ\,g (x)  = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }

h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }

h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}

h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}

h = f\,\circ\,g (-5) = \frac{3}{2}

c) h = g\,\circ\,f(-2)

h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4  }

h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }

h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}

h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}

h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}

h = g\,\circ\,f (-2) = \frac{-3}{-8}

h = g\,\circ\,f (-2) = \frac{3}{8}

6 0
3 years ago
+264=1,707 whats the addend
umka2103 [35]
If you switch it around, it'll be: 1,707 - 264

Subtract:

1,707 - 264 = 1443

Answer = 1,443

~Hope this helped~
5 0
3 years ago
964 two correct wrong place
Anvisha [2.4K]

Answer:

679

Step-by-step explanation:

The goal of this exercise is to find a three digit number given five statements.

1 - We can conclude that two digits out of 964 are correct but in the wrong place.

2 -  One digit out of 147 is correct, but in the wrong place

3 - One digit out of 189 is correct and in the right place. Since 1 is on the same place in 147 and 189, 1 is not the correct digit. The correct digit is either 8 or 9.

4 -   One digit out of 286 is correct, but in the wrong place. Since 8 is on the same place in 189 and 286, 8 is not the correct digit. We can then conclude that 9 is correct (statement 3) and in the right place (third) and that either 2 or 6 are correct but in the wrong place.

5 -  523 are all wrong. We can then conclude that 6 is correct and that is not in the third or second place, which leaves it in the first place.

If 1 and 4 are incorrect, from the second statement, we infer that 7 is the remaining correct digit at the second place.

Therefore the number is 679

7 0
3 years ago
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