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3 years ago

HELP PLEASE PEOPLE THANK UUUUU ‘

Mathematics

1 answer:

Komok [63]3 years ago

3 0

<h2>The required "option B) 60°" is correct.</h2>

Step-by-step explanation:

In question figure,

∠ YUV = 40°, ∠ XUY = 105° and ∠WUX = 155°

To find, the value of ∠ VUW = ?

We know that,

The circle having 360°

∴ ∠ VUW + ∠ YUV + ∠ XUY + ∠WUX = 360°

⇒ ∠ VUW + 40° + 105°+ 155° = 360°

⇒ ∠ VUW + 300° = 360°

⇒ ∠ VUW = 360° - 300°

⇒ ∠ VUW = 60°

∴ The value of ∠ VUW = 60°

Hence, the required "option B) 60°" is correct.

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On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

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4 years ago

Oliver works at a bookstore.He packed 20 identical paperbacks and 9 identical textbooks in a box. The total mass of the books wa

olchik [2.2K]

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The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.

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3 years ago

Express 6^1/3 in simplest radical form.

seropon [69]

<em>Greetings from Brasil</em>

From radiciation properties:

$\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}$

bringing to our problem

$\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}$

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4 years ago

What are the values of a 1 and r of the geometric series? 1 3 9 27 81 a 1 = 1 and r = one-third a 1 = one-third and r = 1 a 1 =

Paha777 [63]

Answer:

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Step-by-step explanation:

Since it’s a geometric series then

a₁ = 1 ( because 1 is the first term of the series)

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Step-by-step explanation:

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2 years ago

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Answer:

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3 years ago