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A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 2000 seats. The students

puteri [66]

Answer:

1340 students

Step-by-step explanation:

since the students left 33% of the seats open, that means they took up 67% of the seats.

67% is 0.67

0.67 * 2,000 = 1340

7 0

3 years ago

1. (1 pt) Which is a solution to the equation y=3x+1 ?A. (3, 10) B. (2, 6) C. (1, 5) D. (0, 3)

frozen [14]

Answer:

the easy way to figure this out is to just plug in answers.

start with a, (10)=3(3)+1

10=9+1

10=10

this makes this a true statement

feel free to try the other options but this is your answer

A. (3,10)

7 0

3 years ago

Which equation describes the same line as y- 5 = -2(x + 4)?

lord [1]

Y-5=-2(x+4)
Y-5=-2x-8
Add 5 to both sides
Y=-2x-3
D

8 0

3 years ago

A blouse require 1 ¼ m of cloth, how many blouses can be made from 21 m of cloth

IrinaK [193]

Answer:

C. 16

Maaf Kalo Salah Y Maaf Ya Lama Cape Itung di

4 0

3 years ago

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and

Brums [2.3K]

Answer:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

$p_v =P(t_9>10.349)=1.34x10^{-6}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=51.6$ represent the sample mean

$s=1.1$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =48$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:

Null hypothesis: $\mu \geq 48$

Alternative hypothesis: $\mu > 48$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

Calculate the P-value

First we find the degrees of freedom:

$df=n-1=10-1=9$

Since is a one-side upper test the p value would be:

$p_v =P(t_9>10.349)=1.34x10^{-6}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

5 0

3 years ago