Ask question

Ask question

All categories

3 years ago

12

NOOOOOOOO LINNNKKKKSSSSSSSS!!!!!!

2 answers:

mr Goodwill [35]3 years ago

7 0

39 ………………………………………………………………

Liula [17]3 years ago

5 0

Answer:

47-(2×4)= 47-8 = 39 the right answer

You might be interested in

What is .368 written in expanded form?

olganol [36]

The expanded form could be:

.300+.060+.008

7 0

3 years ago

Read 2 more answers

Which triangle, if any, has side lengths of 15, 15, and 15?

GalinKa [24]

<span> equilateral triangle is a triangle in which all three sides are equal. In traditional or Euclidean geometry equilateral <span>triangle

</span></span>

4 0

3 years ago

Read 2 more answers

Round 74952 to the nearest 100

sweet-ann [11.9K]

Your answer is 75052

7 0

3 years ago

A mother is 1 3/4 times as tall as her son. Her son is 3 feet tall. How tall is the mother?

Kobotan [32]

In order to find the answer to this question, you need to multiply the fractions. But before we do that, we need to turn the mixed fraction into a proper fraction. 1 3/4 would turn into 7/4 because you multiply the denominator by the whole number and add the numerator. So we come out with:

7/4 x 3/1 = 21/4

Can we simplify 21/4? No, we can't. However, we need to turn it back into a mixed fraction. We can do that by actually dividing the numbers. 21 divided by 4 is 5 with a remainder of 1, so we come out with our answer.

The mom is 5 1/4 feet tall :) Hope this helps!

3 0

3 years ago

Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

$y=-x^2+6x-4$

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

7 0

3 years ago