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Neporo4naja [7]
3 years ago
14

FIND THE EQUATION OF THE LINE!!!USE EXACT NUMBERSEXAMPLE!y= ( )x + ( ) ​

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

y=mx+b is the form to write this equation. M is the slope and B is the y intercept. therefore:

y=4x-9

Step-by-step explanation:

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5 subtracted from w is less than or equal to 16.Write inequality
Vinil7 [7]

Given:

The statement is given as 5 subtracted from w is less than or equal to 16.

The objective is to write inequality for the given statement.

Explanation:

Consider the first statement that is 5 is subtracted from <em>w</em>.

Then, the equation can be written as,

w-5

Explanation:

The result should be less than or equal to 16.

Thus, the final equation can be written as,

w-5\le16

Hence, the obtained inequality is w - 5 ≤ 16.

8 0
1 year ago
If 10% of x is 20, what is 23% of x?<br> A. <br> 33<br> B. <br> 46<br> C. <br> 200<br> D. <br> 230
dusya [7]

Answer:

46

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Decimal form of 92/125
saveliy_v [14]

Answer:

0.736

Step-by-step explanation:

Divide 92/125

8 0
3 years ago
Read 2 more answers
Can you explain to me how to do number two I'm studying for a quiz and I'm stuck on this one.
Furkat [3]

we have (-3,10) and (7,4), then

\begin{gathered} (\frac{x1+x2}{2},\frac{y1+y2}{2}) \\ (\frac{-3+7}{2},\frac{10+4}{2}) \\ (\frac{4}{2},\frac{14}{2}) \\ (2,7) \end{gathered}

5 0
1 year ago
Find the value or measure. Assume all lines that appear to be tangent are tangent. X=
aev [14]

According to the secant-tangent theorem, we have the following expression:

(x+3)^2=10.8(19.2+10.8)

Now, we solve for <em>x</em>.

\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}

Then, we use the quadratic formula:

x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Where a = 1, b = 6, and c = -315.

\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
7 0
1 year ago
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