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gtnhenbr [62]
3 years ago
14

Jerry has taken a random sample of students and determined the number of electives that each student in his sample took last yea

r. There were 19 students in the sample. Here is the data on the number of electives the 19 students took: 6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10. The mean of this sample data is 7.63. Pls help me
What is the sample proportion of students who took fewer than the mean number of electives?

A. `10/19`

B. `6/19`

C. `7/19`

D. There is not enough data to answer this question.
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

A. 10/19

Step-by-step explanation:

The mean is 7.63, so 8,9, and 10 are above that. There are 9 that are either 8, 9, or 10. 19-9=10, therefore making the only possible answer 10/19

I hope this helps you :)

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I don't need you to work it out, just theorem(s) i need to reach the answer :)
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Not sure why such an old question is showing up on my feed...

Anyway, let x=\tan^{-1}\dfrac43 and y=\sin^{-1}\dfrac35. Then we want to find the exact value of \cos(x-y).

Use the angle difference identity:

\cos(x-y)=\cos x\cos y+\sin x\sin y

and right away we find \sin y=\dfrac35. By the Pythagorean theorem, we also find \cos y=\dfrac45. (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if \tan x=\dfrac43, then (by Pythagorean theorem) \sec x=\dfrac53, so \cos x=\dfrac35. And from this, \sin x=\dfrac45.

So,

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The linear equality y < 3x + 2 is represented by the graph attached.

<h3>What is an equation?</h3>

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