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Ber [7]
4 years ago
5

Find all complex solutions of 5x^2-6x+2=0.

Mathematics
1 answer:
gregori [183]4 years ago
8 0
We use quadratic formula for that one
remember that √-1=i

so

for
ax^2+bx+c=0
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so
given
5x^2-6x+2=0
a=5
b=-6
c=2

x=\frac{-(-6)+/-\sqrt{(-6)^2-4(5)(2)}}{2(5)}
x=\frac{6+/-\sqrt{36-40}}{10}
x=\frac{6+/-\sqrt{-4}}{10}
x=\frac{6+/-2i}{10}

x=\frac{3}{5}+\frac{i}{5}, \frac{3}{5}-\frac{i}{5}
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\huge\text{Hey there!}

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\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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