Answer:
<u>The two numbers are 23 and 56</u>
Step-by-step explanation:
Let's say the two numbers are A and B.
We are told:
1) A+B=79
2) 3A+5B=283
Let's take the first expression and solve for A:
A+B=79
A=79-B
Now use this value of A in the second expression:
3A+5B=283
3(79-B)+5B=283
237-3B+5B=283
2B = 46
B = 23
Since B=23, we know from 1) that
A+B=79
A+23=79
A = 56
<u>CHECK:</u>
Does A+B=79?
56+23 = 79? <u>YES</u>
Does 3A+5B=283?
3(56)+5(23)=283
168 + 115 = 283? <u>YES</u>
1427 = (F) (+ F + 60) (2F - 50) (+ 3F)
<em>Each pair of brackets represents one of the classes - F meaning Freshmen Class. It has been split into brackets for demonstrational purposes - nothing is being multiplied.</em>
F is an unknown number and each other class size is based off of that so we put it in algebraic terms in order to work it out.
1 - Freshmen Class
2 - Sophomore Class (Freshmen Class + 60 more students)
3 - Junior Class ( Twice the size of the Freshmen Class - 50 students)
4 - Senior Class (Three times the size of the Freshmen Class)
All this can be simplified to 7F + 10 = 1427
1427 - 10 = 1417
1417/7 = 202.428....
Is there a mistake in the question?
Following the question with 202 as the answer - the number 1424 is reached
If increased to 203 - 1431 is reached.
The answer shouldn't include half a person.
Given :
Initial length of electric cable needed, 
.
Later, Sally is told that the homeowner has decide to cut back from a three-car garage to a two-car garage, which will eliminate two branch circuits, one of 23 feet and the other of 34 feet.
To Find :
How many feet of wire will be needed now.
Solution :
Wire needed is given by :
Required = Total wire - ( length of 1nd branch + length of 2nd branch )
Required = 550 - ( 23 + 34 )
Required = 550 - ( 57 ) ft
Required = 443 ft
Therefore, length of wire required is 443 ft.
Hence, this is the required solution.
Answer:
5 hotdogs and 2 tacos
Step-by-step explanation:
