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zvonat [6]
3 years ago
12

I don't understand this please???

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0
1 because 3/4 and 1 1/3:
It would be literally 1 1/3 divided by 4
Then you could get 1/3
So then you multiply 1/3 by 3
So you would get 1
Marta_Voda [28]3 years ago
4 0
So 3/4 of 1 and 1/3
'of' can be roughly translated into multiply so
3/4 times 1 and 1/3 or
3/4 times 4/3=12/12=1

the answer is 1 cup of rasins
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There are 5 red balls, 7 blue balls, and 4 white balls What is the ratio of blue balls to total balls?
Pavlova-9 [17]

Answer:

its 7: 16

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What's 84 divided by 7 show the work plz
Snowcat [4.5K]
Ok, this is what you do, 

      
7(^^^^^
      84
7 goes into 8 1 time so it would be this

      1
7(^^^^
      84
     - 7

and it leaves you with 14
   
    
     1
7(^^^^
       14
then how many time does 7 go into 14? 2 times

so it would be


      12
7(^^^^
       14
       -14
AND YOUR ANSWER IS 12.



7 0
3 years ago
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How many digits are in 385,604 ?
Kaylis [27]
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6 0
3 years ago
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If f(x)=5x+1 and g(x)=2f(x)+5 then g(-1)=
ollegr [7]
We know f(x)=5x+1. Plug in f(x) in the g(x) function.
We get g(x)=2(5x+1)+5 Distribute the 2 to 5x and 1.
g(x)=10x+2+5
Simplify to get g(x)=10x+7
Now, we plug in -1 for x.
g(-1)=10(-1)+7
g(-1)=-10+7
g(-1)=-3 
4 0
3 years ago
What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

7 0
3 years ago
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