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zvonat [6]
3 years ago
12

I don't understand this please???

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0
1 because 3/4 and 1 1/3:
It would be literally 1 1/3 divided by 4
Then you could get 1/3
So then you multiply 1/3 by 3
So you would get 1
Marta_Voda [28]3 years ago
4 0
So 3/4 of 1 and 1/3
'of' can be roughly translated into multiply so
3/4 times 1 and 1/3 or
3/4 times 4/3=12/12=1

the answer is 1 cup of rasins
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Trigonometry please help
kotykmax [81]

Answer:

7.5

Step-by-step explanation:

x = 10 \tan \: 37 \degree \\  \\  \therefore \: x = 7.535540501 \\  \\ \therefore \: x  \approx 7.5

3 0
3 years ago
Read 2 more answers
10 points Help me with all I mark you as brainlist please
san4es73 [151]

Answer: Question 1

a)5.47

b)4.53

Step-by-step explanation:

5 0
3 years ago
Hi please help me no links thank you
olya-2409 [2.1K]

Step-by-step explanation: (I'm not gonna' do it <em>all</em> for you tho)

to convert from <u>percent to fraction</u>:

70% = \frac{70}{100} =\frac{7}{10}

to convert from <u>fraction to percent</u>:

\frac{11}{20}=\frac{55}{100} = 55%

to convert from <u>fraction to decimal</u>:

\frac{3}{25} =\frac{12}{100} =0.12

to convert from <u>decimal to fraction</u>:

1.25=\frac{125}{100} =1\frac{25}{100} =1\frac{1}{4}

to convert from <u>percent to decimal</u>:

0.2% = \frac{0.2}{100} =0.002

to convert from <u>decimal to percent</u>:

0.4= (0.4*100)% = 40%

With that, you can solve the rest on your own

4 0
3 years ago
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
3 years ago
If k represents a number then write an expression for the ratio of 3 less than k to 2 more than k
EleoNora [17]

The key words you should notice when looking at this word problem are “less than.” This means that the order is flipped, so “3 less than k” means “k minus 3.”

The expression for the ratio is k-3:k+3

Hope this helps

3 0
3 years ago
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