Which figure shows a reflection of pre-image DEFG over the x-axis?

a truck delivers bags of apples and oranges to the grocery store. Each bag has twice as many apples as oranges. Each bag contain

Serhud [2]

Answer: 630 apples in the delivery

Step-by-step explanation: There are 15 pieces of fruit. 15 is the only number by 3 to get a even 5. So their are 5 oranges in each bag and 10 apples(because they are doubled) now there are 10 apples in each bag and 63 bags. You multiply 63x10=630

Therefore 630 is your answer

8 0

3 years ago

HIIIIII 2 QUESTIONS IN THE 2 PICS HELP PLS

skelet666 [1.2K]

Answer:

(1)C- Trapezoid

(2)D-20 square feet

Step-by-step explanation:

<u>Question 1</u>

A cross-section of a rectangular pyramid cut perpendicular to the base but not passing through the top will have two parallel sides where one of the sides will be longer. Therefore, the shape which describes the cross-section will be a trapezoid.

<u>Question 2</u>

The base of the Triangle = 5 feet

Height of the Triangle = 8 feet

$\text{Area of a triangle}=\dfrac12 \times $Base \times Height\\=\dfrac12 \times 5 \times 8\\=20 ft^2$

3 0

3 years ago

Elis [28]

The size of the car engine in cubic inches is 263.6 2 cubic inches

<h3>How to determine the size of the car engine in cubic inches?</h3>

The given parameters are

Volume = 4320 cubic centimeters

By general conversion rule, we have

1 cubic centimeter = 0.0610237 cubic inches

Multiply both sides of 1 cubic centimeter = 0.0610237 cubic inches by 4320

4320 * 1 cubic centimeter = 0.0610237 cubic inches * 4320

Evaluate the product

4320 cubic centimeters = 263.6 2cubic inches

Substitute 4320 cubic centimeters = 263.6 2cubic inches in Volume = 4320 cubic centimeters

Volume = 263.6 2cubic inches

Hence, the size of the car engine in cubic inches is 263.6 2cubic inches

Read more about volume at:

brainly.com/question/1972490

#SPJ1

5 0

1 year ago

In ⊙O, ST and VT are tangents. m∠STV = 22°. Find the value of a, b, and m∠SOV.

Rasek [7]

Answer:

$\huge \orange {\boxed {a =202\degree}}$

$\huge \purple {\boxed { b = 158\degree}}$

$\huge \red {\boxed {m\angle SOV = 158\degree}}$

Step-by-step explanation:

In $\odot$ O, ST and VT are tangents at points S and V respectively.

$\therefore OS\perp ST, \:and\: OV\perp VT$

$\therefore m\angle OST=m\angle OVT = 90\degree$

In quadrilateral OSTV,

$m\angle SOV +m\angle OST+m\angle OVT+m\angle STV = 360\degree$

(By interior angle sum postulate of a quadrilateral)

$m\angle SOV +90\degree +90\degree +22\degree = 360\degree$

$m\angle SOV +202\degree = 360\degree$

$m\angle SOV = 360\degree-202\degree$

$\huge \red {\boxed {m\angle SOV = 158\degree}}$

$\because b = m\angle SOV$

(Measure of minor arc is equal to measure of its corresponding central angle)

$\huge \purple {\boxed {\therefore b = 158\degree}}$

$\because a + b= 360\degree$

(By arc sum property of a circle)

$\therefore a = 360\degree - b$

$\therefore a = 360\degree -158\degree$

$\huge \orange {\boxed {\therefore a =202\degree}}$

6 0

2 years ago

Peppi Unu JUIC luyeler, TIUW TUNTY LeuspOU15 WII Ulere ve dil dll?

kotykmax [81]

Answer:

What's the Question?

Step-by-step explanation:

I don't Understand what the Question Is.

6 0

3 years ago