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Bumek [7]
2 years ago
5

Another way to write 300 + 70 + 5/10 + 8/100

Mathematics
1 answer:
Alja [10]2 years ago
8 0

Answer:

A. 370.58

Step-by-step explanation:

Hope that helps

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Raul is making chocolate chip pancakes. The number of chocolate chips he uses is proportional to how many ounces of mix he makes
Gemiola [76]

Answer:

12 = 5k/2

24 = 5k

Step-by-step explanation:

Raul is making chocolate chip pancakes.

The number of chocolate chips he uses is proportional to how many ounces of mix he makes.

Hence,

Chocolate chips ∝ Number of Ounces

Chocolate chips = c

Number of Ounces = m

= cm

c = km

Where k = Constant of Proportionality

The recipe said that for every 2 1/2 ounces of the mix, 12 chocolate chips be added.

Hence

12 = 21/2 × k

12 = 5/2 × k

12 = 5k/2

Cross multiply

12 × 2 = 5k

24 = 5k

The equation that represents the relationship between c the number of chocolate chips and m the number of ounces is

12 = 5k/2

24 = 5k

8 0
3 years ago
Plz help me with this problem
mixer [17]
I don’t know what is your problem is
7 0
3 years ago
Can someone help me out
Nana76 [90]

Answer:

it is D

(1.5-6)/-2-4 =0.75

4 0
2 years ago
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
Y=x+5 and y=1/2x+4 <br> solved and graphed
solniwko [45]
The interception point or solving for X?
6 0
3 years ago
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