Question

Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show your work

Answer 1

The diagonals of a parallelogram are congruent

The length WY is 32

How to determine the length WY

Given that:

$WA = x^2 - 48$ and

$AY = x^2 - 6x$

Then, we have:

$x^2 - 48 = x^2 - 6x$diagonal

Subtract x^2 from both sides

$- 48 =- 6x$

Divide both sides by -6

$x = 8$

The length WY is calculated as:

$WY=2 * WA$

So, we have:

$WY=2 * [x^2 - 48]$

Substitute 8 for x

$WY=2 * [8^2 - 48]$

Simplify

$WY=32$

Hence, the length WY is 32

Read more about parallelograms at:

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