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Mila [183]
2 years ago
8

Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y

our work

Mathematics
1 answer:
netineya [11]2 years ago
6 0

The diagonals of a parallelogram are congruent

The length WY is 32

<h3>How to determine the length WY</h3>

Given that:

WA = x^2 - 48 and

AY = x^2 - 6x

Then, we have:

x^2 - 48 = x^2 - 6xdiagonal

Subtract x^2 from both sides

- 48 =- 6x

Divide both sides by -6

x = 8

The length WY is calculated as:

WY=2 * WA

So, we have:

WY=2 * [x^2 - 48]

Substitute 8 for x

WY=2 * [8^2 - 48]

Simplify

WY=32

Hence, the length WY is 32

Read more about parallelograms at:

brainly.com/question/10062747

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Step-by-step explanation:

the answer for solving a quadrilateral

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so the base is 2x-8 and the height is 3x+8

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expand

6x^2-8x-64

Hope that helps :)

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Find the equation of the line passing through the points (15,-25) and (-12,11). Write your answer in the form of y=mx+b
schepotkina [342]
(15,-25)(-12,11)
slope = (11 - (-25) / (-12 - 15) = - 36 / 27 which reduces to - 4/3

y = mx + b
slope(m) = -4/3
use either of ur points (15,-25)...x = 15 and y = -25
now we sub and find b, the y int
-25 = -4/3(15) + b
-25 = - 20 + b
-25 + 20 = b
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Which two of the following numbers round to 36.2 if were rounding to the nearest tenth
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Step-by-step explanation:

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Let f () = + 5 and g(x) = 2x - 3<br> Find f (x) g(x)
Nina [5.8K]

Answer:

2x^{2}+7x-15

Step-by-step explanation:

I presume f(x)=x+5 and g(x) =2x-3 and the question is f(x)*g(x)

f(x)*g(x)

(x+5)(2x-3)

distribute

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2x^{2}+7x-15

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