Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y
1 answer:
The diagonals of a parallelogram are congruent
The length WY is 32
<h3>How to determine the length WY</h3>
Given that:
and

Then, we have:
diagonal
Subtract x^2 from both sides

Divide both sides by -6

The length WY is calculated as:

So, we have:
![WY=2 * [x^2 - 48]](https://tex.z-dn.net/?f=WY%3D2%20%2A%20%5Bx%5E2%20-%2048%5D)
Substitute 8 for x
![WY=2 * [8^2 - 48]](https://tex.z-dn.net/?f=WY%3D2%20%2A%20%5B8%5E2%20-%2048%5D)
Simplify

Hence, the length WY is 32
Read more about parallelograms at:
brainly.com/question/10062747
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YZ = 16. The triangles are congruent. This would be AAS so YZ = 16 because of CPCTC.
Answer:it is 34
And that's it
A=v1-v0/t
a*t=v1-v0
(a*t)+v0=v1