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Mila [183]
2 years ago
8

Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y

our work

Mathematics
1 answer:
netineya [11]2 years ago
6 0

The diagonals of a parallelogram are congruent

The length WY is 32

<h3>How to determine the length WY</h3>

Given that:

WA = x^2 - 48 and

AY = x^2 - 6x

Then, we have:

x^2 - 48 = x^2 - 6xdiagonal

Subtract x^2 from both sides

- 48 =- 6x

Divide both sides by -6

x = 8

The length WY is calculated as:

WY=2 * WA

So, we have:

WY=2 * [x^2 - 48]

Substitute 8 for x

WY=2 * [8^2 - 48]

Simplify

WY=32

Hence, the length WY is 32

Read more about parallelograms at:

brainly.com/question/10062747

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