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Oksi-84 [34.3K]
3 years ago
14

Can you please help meee

Mathematics
2 answers:
nlexa [21]3 years ago
5 0
I think it's the second one I'm pretty sure
grandymaker [24]3 years ago
3 0
The answer should be 23+p but im not 100% sure
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How many different 5-digit numbers can be written using only numbers 0, 1, 2, 3, and 4, if number should contain each of these n
gizmo_the_mogwai [7]

Answer:

3125

Step-by-step explanation:

5* 5* 5* 5 = 3125

8 0
3 years ago
Solve for x. Help me now Please!!
mamaluj [8]

Answer:

i think there was a glith or something. try re asking the question!

8 0
3 years ago
Select all of the correct answers.
Korvikt [17]

Question:

Martin uses 5/8 of a gallon of paint to cover 4/5 of a wall. what is the unit rate at which Martian paints in walls per gallon

Answer:

0.78125  walls per gallon

<em></em>

Step-by-step explanation:

Given

Paint = \frac{5}{8}\ gallon

Wall = \frac{4}{5}

Required

Determine the unit rate

This is calculated as:

Unit\ Rate = \frac{Wall}{Paint}

Substitute values for wall and paint

Unit\ Rate = \frac{5/8}{4/5}

Simplify:

Unit\ Rate = \frac{5}{8}/\frac{4}{5}

Change to *

Unit\ Rate = \frac{5}{8}*\frac{5}{4}

Unit\ Rate = \frac{5*5}{8*4}

Unit\ Rate = \frac{25}{32}

Unit\ Rate = 0.78125

<em>Hence, the unit rate is: 0.78125  walls per gallon</em>

4 0
3 years ago
Muchii unui cub are lungimea de 16cm.Care este perimetrul unei freţe a cubului? va rog rapid dau coroana
MAVERICK [17]

Răspuns:

64 cm

Explicație pas cu pas:

Perimetrul fiecărei margini a unui cub:

4 * lungime laterală

Lungime laterală = 16cm

Prin urmare, perimetrul va fi:

4 * 16cm

= 64cm

6 0
3 years ago
A rectangular piece of land is to be fenced using two kinds of fencing. Two opposite sides will be fenced using standard fencing
damaskus [11]

Answer:

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

Step-by-step explanation:

Given that,

Two opposite sides of rectangular land will be fenced using standard fencing that costs $6 per m while the other two side will require heavy duty fencing that costs $9 per m.

Let the length and width of the rectangular x and y respectively.

Then total cost for fencing = \$(2x\times 6+2y\times 9)

                                            =$(12x+18y)

Then,

12x+18y= 9,000

⇒ 2x+3y=1,500     [ cancel out common factor 6]

⇒3y= 1500 - 2x

\Rightarrow y=\frac{1500-2x}{3} ....(1)

The area of the rectangular land is = Length × width

                                                          = xy

Let,

A=xy

Putting the value of y

A=x.\frac{1500-2x}{3}

\Rightarrow A=\frac13(1500x-2x^2)

Differentiating with respect to x

A'=\frac13(1500-4x)

Again differentiating with respect to x

A''=-\frac43

Now we have to determine the critical value of A.

For critical value set A'=0

\frac13(1500-4x)=0

⇒1500-4x=0

\Rightarrow x=\frac{1500}{4}

\Rightarrow x=375 m

Since, A''|_{x=375}=-\frac43. at x=375 m the area of the rectangular piece of land is maximum.

From equation (1) we get when x=375

y=\frac{1500-2\times 375}{3}

⇒y=250 m

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

3 0
3 years ago
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