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3 years ago

A solid has 16 faces and 14 vertices. How many edges does the solid have? A. 14 edges B. 18 edges C. 20 edges D. 28 edges

1 answer:

7 0

The formula to use is F +V -E = 2

F = Faces = 16
V = Vertices = 14
E = edges = Unknown

We can fill in the information we have and solve for edges:

16 + 14 - E = 2

Add 16 and 14:

30 - E = 2

E = 30-2

E = 28

There are 28 edges

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3 years ago

Joe Morris Plains to fertilize his 1800 foot wide Hayfield he will be using his truck spreader that spreads of 60-foot strip how

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3 years ago

Find the value of c so that the polynomial p(×) is divisible by (x-4). p(×)=cx^3-15x-68

Dvinal [7]

Answer:

Step-by-step explanation:

x-4=0

x=4

p(x)=cx^3-15x-68=0

p(x)=c(4)^3-15(4)-68=0

p(x)=64c-60+68=0

p(x)=64c+8=0

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3 years ago

Why is isolating the y-variable to graph is important

dusya [7]

Answer:

It is the easiest way to graph an equation.

Step-by-step explanation:

Isolating the y variable is also slope-intercept form.

Slope intercept form is the easiest form to use when graphing.

y = mx + b

m is the slope, b is the y-intercept.

it makes it way easier to graph an equation when it is in slope intercept form.

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3 years ago

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

Mandarinka [93]

Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

$a_n = a_m + (n-m)d$

a3 = -12 and a8 = -37

First we find the common difference. So

$a_n = a_m + (n-m)d$

$a_8 = a_3 + (8-3)d$

$-37 = -12 + 5d$

$5d = -25$

$d = -\frac{25}{5}$

$d = -5$

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

6 0

3 years ago