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mart [117]
2 years ago
14

Linear graph and transformation

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
8 0

Answer:

The graph of a linear function (a line) can be moved around the coordinate grid. This is called a transformation. There are three basic transformations: translation (sliding the line around), reflection (flipping the line), and scaling (stretching the line). You can move (transform) the line vertically or horizontally.

meriva2 years ago
7 0

Answer:

Graphing a Linear Function Using Transformations. Another option for graphing is to use transformations of the identity function f(x)=x f ( x ) = x . A function may be transformed by a shift up, down, left, or right. A function may also be transformed using a reflection, stretch, or compression.

Step-by-step explanation:

<h2>❣️(◍Jess bregoli ◍)❣️</h2>

#keep learning!!

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A 24-ounce mocha beverage with whipped cream has 25% of the calories allowed on a 2,000-calorie-per-day diet. What percentage of
likoan [24]
We can find the amount of calories it has by taking 25% of 2000:
0.25 x 2000
= 500

Percentage of 2500 calorie diet:
500/2500 x 100
= 20%

The drink constitutes 20% of a 2500 calorie per day diet..
3 0
3 years ago
Read 2 more answers
Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.
Leokris [45]
Standard form is, hold a sec

x=2 is directix
that means it opens left or right
so we must use
(y-k)²=4p(x-h)
where vertex is (h,k) and p is distance from focus to vertex
also shortest distance from vertex to directix
the shortest distance from focus to directix is 2p
if p>0 then the parabola opens right
if p<0 then pareabola opens left

so
(-2,0) and x=2
the distance is 4
4/2=2
p=2
wait, positive or negative
focus is to the left of the directix so p is negative
p=-2

vertex is 2 to the right of the focus and 2 to the left of directix
vertex is (0,0)

so
(y-0)²=4(-2)(x-0) or
y²=-8x is da equation
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4 0
2 years ago
Hii please help i’ll give brainliest
Novosadov [1.4K]
I think the answer would be 1/2 but i’m not sure if that’s what it’s asking
4 0
3 years ago
Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the
Likurg_2 [28]

Answer:

(a)  moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, P(X)=\frac{1}{6}

(a) Moment generating function can be written as M_{x}(t).

M_x(t)=\sum_{x=1}^{6} P(X=x)

M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}

M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) Now, find E(X) \text { and } E\((X^{2}) using moment generating function

M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)

M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)  

\Rightarrow E(X)=\frac{21}{6}

M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)

M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)

\Rightarrow E\left(X^{2}\right)=\frac{91}{6}  

Hence, (a) moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right).

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

6 0
3 years ago
The triangles below are similar. What is the length of ? A. 17 cm C. 19 cm B. 18 cm D. 20 cm
denis-greek [22]

Answer:

B. 18 cm.

Step-by-step explanation:

Because they are similar, we can say that segment AC corresponds to segment DF, and segment AB corresponds to segment ED. So, we can set up a proportion.

\frac{16}{24} =\frac{12}{x}

\frac{2}{3} =\frac{12}{x}

2 * x = 12 * 3

2x = 36

x = 18

So, the length of ED is B. 18 cm.

Hope this helps!

4 0
3 years ago
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