Area of the middle rectangular section = length x width = 35 x 20 = 700 square cm.
The radius of the circular sections is 25 cm
Area of a full circle is pi x r^2 = 3.14 x 25^2 = 1962.5 square cm.
There are two quarter circles which is 1/2 of a circle. The area of those would be 1962.5/2 = 981.25 square cm.
Total area of the figure = 700 + 981.25 = 1681.25 square cm
The first option is correct.
Moving 1.5 units to the left (or -1.5 units to the right).
Moving 1 unit down (or -1 unit up).
Therefore you get the result of (-1.5, 1) as is the location of the rink.
Its pretty simple
9x-7y = 22
x + 3y = -24
(9x-7y = 22)
-9(x + 3y = -24)
= -9x -27y = 216
+ 9x-7y = 22
= -34y = 238
= / -34 = 238/-34
y = -7
now plug -7 in one of the equation
x + 3(-7) = -24
x -21 = -24
+21. +21
x = -3
so answer is x = -3 and y = -7
Answer:
(3 V/ 4 pi) ^(1/3) = r
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
We want to solve for r
Multiply each side by 3/4
3/4 V = 4/3*3/4 pi r^3
3/4 V = pi r^3
Divide each side by pi
3/4 V/ pi = pi/pi r^3
3 V/ 4 pi = r^3
Take the cube root of each side
(3 V/ 4 pi) ^(1/3) = ( r^3) ^1/3
(3 V/ 4 pi) ^(1/3) = r
