When you have a coefficient in front of the "x^2" value, you have to multiply it by the end value (4)
so you want a set of integers that will add up to 29, by multiple to (7 x 4) = 28
The only numbers like that are 28 and 1, they add up to 29 and multiply to 29
Therefore, rewrite it like this 7x^2 + 28x + x + 4
and then factor out the 7x in the first two terms, to get this
7x(x+4) + x + 4, then factor out 1 in the latter two terms to get this:
7x(x+4) +1(x+4), then use grouping to combine what you've got:
The factors are: {{ (7x+1)(x+4) }}
Answer:
Step-by-step explanation:
24 + 36 = 12*2 + 12*3
= 12* (2 + 3)
= 12 * 5
= 60
Answer:
L= 10 in
W= 7 in
Step-by-step explanation:
Given data
let the widht be x
W= x
L= x+3
P=34 in
We know that
P=2L+2W
34= 2(x+3)+ 2(x)
34= 2x+6+2x
collect like terms
34= 4x+6
34-6= 4x
28= 4x
divide both sides by 4
x= 28/4
x=7
Put x= 7 in
L= x+3
L= 7+3= 10
Hence the width is 7in the length is 10 in
Let's solve for x.
5x+15y=12
Step 1: Add -15y to both sides.
5x+15y+−15y=12+−15y
5x=−15y+12
Step 2: Divide both sides by 5.
5x
5
=
−15y+12
5
x=−3y+
12
5
Answer:
x=−3y+12/5
Let's solve for y.
5x+15y=12
Step 1: Add -5x to both sides.
5x+15y+−5x=12+−5x
15y=−5x+12
Step 2: Divide both sides by 15.
15y
15
=
−5x+12
15
y=
−1
3
x+
4
5
Answer:
y=-1/3x+4/5
Hope this helps!
-Josh
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