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Sholpan [36]
3 years ago
7

Need help now please guys

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0

Answer:

A = Y axis

D = X axis

C = origin

B = quadrant I (?)

Step-by-step explanation:

MAVERICK [17]3 years ago
3 0

Answer:

A is the y-axis

C is the origin

D is the x-axis

Step-by-step explanation:

I do not know what B is sorry

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5x^2 + 9x = -4<br><br> What is the “c” value for the following quadratic equation.
ohaa [14]

Answer:

c=4

Step-by-step explanation:

5x^2 + 9x = -4

We need to write this in the form

ax^2 +bx+c = 0

So add 4 to each side

5x^2 + 9x+4 = -4+4

5x^2 + 9x+4 = 0

a =5   b=9 and c =4

6 0
3 years ago
In this situation, simple interest is calculated yearly.
d1i1m1o1n [39]
Answer: 3,840

8000 * 4 * 12 = 384,000

384,000 / 100 = 3.840
7 0
2 years ago
Read 2 more answers
A surveyor sights the far bank of a river at an angle of 110° to the near bank. She then moves 75 feet upriver and sights the sa
Leya [2.2K]

Answer:

Correct answer is 54.82 ft.

Step-by-step explanation:

First of all, let us label the diagram and do the construction as per the attached answer image.

Let us consider \triangle ABC:

\angle B = 90^\circ\\\angle ACB = 180-110 = 70^\circ

Let side AB = d ft and let side BC = x ft

We need to find AB to find the shortest distance across the river.

Using trigonometric identity of tangent:

tan\theta = \dfrac{Perpendicular}{Base}

tan 70 = \dfrac{d}{x}\\\Rightarrow x = \dfrac{d}{tan70} = 0.36d ..... (1)

Now, let us have a look at another right angled triangle ABD:

Let us consider \triangle ABC:

\angle B = 90^\circ\\\angle ADB = 180-150 = 30^\circ

side AB = d ft and side BD = x+75 ft

Using trigonometric identity of tangent:

tan\theta = \dfrac{Perpendicular}{Base}

tan 30 = \dfrac{d}{x+75}\\\text{Using equation (1)}:\\0.577 = \dfrac{d}{0.36d+75}\\\Rightarrow 0.207d + 43.27 = d\\\Rightarrow 0.793d = 43.27\\\Rightarrow d \approx 54.82\ ft

Correct answer is 54.82 ft.

7 0
3 years ago
hello I need help with question 2 attached is the tables created in question one which I need to base question 2 off of. 2. Find
Vadim26 [7]

The given functions are:

\begin{gathered} f(x)=3x+2 \\ g(x)=\frac{x-2}{3} \end{gathered}

The domain is the set of all possible values that the independent variable (x) can take.

The range is the set of values that the function will take.

For these functions, the domain is all real numbers since they both will work with any positive or negative number (-∞,∞). Thus, the range is the same, all real numbers (-∞,∞).

But, for the purpose of the question let's analyze the interval you took for the table of values:

For f(x) function, you take x-values from -3 to 3, then the domain in this interval is [-3,3] and the range is the output values (f(x)), then the range is [-7,11].

For g(x) function, you take x-values from -7 to 11, then the domain in the interval is [-7,11] and the range (the g(x) values obtained) is [-3,3].

As can be noticed, in the interval the domain of the f(x) functions is the same as the range of the g(x) function, and the domain of the g(x) function is the same as the range of f(x) function. This happens because g(x) is the inverse function of f(x).

3 0
1 year ago
Multiple Choice Suppose y varies directly as x. if y = 5 when x=8, find y when x=64
Juliette [100K]

Answer:

Step-by-step explanation:

y∞x

then

y=kx (with k as constant)

y=5 when x=8

⇒Putting this in the first equation

⇒5=k×8

⇒k=5/8

Now

y=? when x=64

Putting x=64 in the first equation

y=kx

⇒y=(5/8)×64

We get

y=40

Hope u understand

6 0
3 years ago
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