A. 2 and 8
It’s the pair of angles on the outer side of each of those two lines but on opposite of the transversal.
A work applied on the cart = 20.8x0.636
Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to

we have



substitute in the formula of volume
----> equation B
substitute equation A in equation B

solve for y


Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x

therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Answer:
x = 14
Step-by-step explanation:
Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.
The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:
138 = (376 -23x) +(x^2 -8x)
Subtracting 138 and collecting terms we have ...
x^2 -31x +238 = 0
For your calculator, a=1, b=-31, c=238.
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<em>Additional comment</em>
You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.
For x=14, the marked angles are A = 84°, C = 54°.
Answer
5/20 so 25%
Explanation