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aliina [53]
3 years ago
15

[(9 + 5) x (4 - 2)] x (5-1)]

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

112

Step-by-step explanation:

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Help peeps i shall give brainalist .-_-.
Oksana_A [137]
The answer is B
R=89.49/2 pi
It give you the circumference and you need to find the radius
5 0
3 years ago
LOOK AT THE PICTURE
OleMash [197]

Answer:

I don't think any of the answers here are right. They aren't a proportional relationship since they don't pass through the origin. So I would believe the answer would be C. Sorry if I'm wrong!!

Step-by-step explanation:

I learned about this stuff :D

6 0
3 years ago
Read 2 more answers
Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and
Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0
4 years ago
Suppose that a process is currently operating at a 3.5-sigma quality level, and it is planned to use improvement projects to mov
jenyasd209 [6]

Answer:

11,373 PPM

Step-by-step explanation:

The following  formula is used to compute the Proportion of error-free units given the sigma level in Excel.

<em>  The proportion of error-free units = NORMSDIST(Sigma Level - 1.5) </em>

Suppose that a process is currently operating at a 3.5-sigma quality level.

The proportion of error-free units for this process is

                           NORMSDIST(3.5 - 1.5) = 0.977250

Therefore, the rejection rate is equal to

                  1 - 0.977250 = 0.022750

or 22750 PPM.

Now, consider a 6-sigma level process.

The proportion of error-free units equals

                     NORMSDIST(6.0 - 1.5) = 0.9999966

and the rejection rate is

                             1 - 0.9999966 = 3.4 PPM

Hence, reduction is PPM required per year , that is

                              \dfrac{22750 - 3.4}{2} = 11,373 PPM

reduction per year

7 0
3 years ago
Plz answer its 5th grade math​
MAVERICK [17]

Answer:

the answer is c I think for that problem

6 0
4 years ago
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