Answer:
![\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given [Missing from the question]
![\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Required

This implies that, we form a new matrix where the second row of the new matrix is a product of -3 and the second row of the previous matrix.
So, we have:
![Initial =\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=Initial%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3*1&-3*3&-3*-1&|-3*-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%2A1%26-3%2A3%26-3%2A-1%26%7C-3%2A-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
8. 1 5
4/33.00
32
10
8
20
20
0
8.15+8=10.15
The answer is 10.15 inches long for each frame.
Answer:
False You just multiply the numbers by 5/3 I am pretty sure.
Hope it helps Have an wonderful day! :)
Answer:
Step-by-step explanation:
When the interest compounds continuously, our formula is

If we start with 10000 and are looking for how long, t, it takes to double, we are looking for how long it will take for our account to have 2 times 10000. That's 20000. Therefore, our equation is

Divide both sides by 10000 to get

Take the natural log of both sides to "undo" that e:

Again, since ln and e undo each other what we have now is
ln(2) = .11t and
so
t = 6.3 years