D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Answer: 1.25 or 5/4
Steps:
Move the -3x to the other side by adding it which gives you 4x=5. Then divide by 4 to have the x alone which gives you the answer. Hopes this helps :)
The area of the cross section is in the shape of a triangle.
Translating this sentence into symbols: 2(x+3) = x - 5
So 2x + 6 = x - 5 and x = -11
Check: Is 2(-11+3) = -11 -5? Is -16 = -16? YES. x =-11 is right.
