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3 years ago

X = - 3x+5 What is the value of x

2 answers:

8 0

Answer: 1.25 or 5/4
Steps:
Move the -3x to the other side by adding it which gives you 4x=5. Then divide by 4 to have the x alone which gives you the answer. Hopes this helps :)

lidiya [134]3 years ago

5 0

To find the value of x, you need to isolate/get the variable "x" by itself in the equation:

x = -3x + 5 Add 3x on both sides to get "x" on one side of the equation

x + 3x = -3x + 3x + 5

4x = 5 Divide 4 on both sides to get "x" by itself

$\frac{4x}{4}=\frac{5}{4}$

$x=\frac{5}{4}$

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Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at $(0,1)$ .

The graph has an x-intercept at $(-7,0)$ .

Step-by-step explanation:

Given: The graph is $y=\sqrt[3]{x-1}+2$

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of $(-\infty, \infty)$ .

To find the y-intercept: To find the y-intercept, substitute $x=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}$

Thus, the y-intercept is $(0,1)$

To find the x-intercept: To find the x-intercept, substitute $y=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}$

Thus, the x-intercept is $(-7,0)$

8 0

3 years ago

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The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime

Aleks [24]

Answer:

64√2 or 64 StartRoot 2 EndRoot

Step-by-step explanation:

A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.

Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.

X=(128√2)/2= 64√2 cm.

Since X is the leg, the answer would be 64√2

3 0

3 years ago

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Los alumnos de 1° G han organizado una campaña para conseguir dinero y enviarlo a un proyecto de cooperación. Para ello han vend

goldenfox [79]

Answer:

Step-by-step explanation:

To find the number of color pencils sold you simply multiply the number of color pencils by the number of 1st classes:

$#color\ pencils\ sold=(color\ pencils\ sold\ per\ class)(number\ of \ 1st\ G\ classes)$

- each class sold 7 color pencils

- there are seven 1st G classes

Then, you replace in the formula and you obtain:

$color\ pencils\ sold=(7)(7)=49$

hence, there were 49 color pencils sold

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3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
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№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
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№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
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Answer: x₁ = 1 + √3.5
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Answer:

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Step-by-step explanation:

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3 years ago

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