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ipn [44]
3 years ago
9

Thomas used a can to feel his new fish tank with water. The fish tank holds 11 gallons of water. His can hold 1/5 of a gallon. H

ow many times will Thomas have to feel his canned to put 11 gallons of water in a fish tank?
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

55

Step-by-step explanation:

If the can holds 1/5 of a gallon, he will have to fill it up 5 times to fill 1 gallon of the tank. Since the tank holds 11 gallons, he will have to fill up the can 5 × 11 = 55 times.

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Determine f(4), f(-5) and f(-2/3)
anyanavicka [17]

Answer:

Y would just equal 6. It says so. Imagine that line where the line is just at y=-6. And imagine all of the points on that line with 4, 5, and -2/3 as the x.

Step-by-step explanation:

5 0
3 years ago
A bag contains five ping-pong balls numbered 1 to 5. Two balls are removed to form a two digit number. The smallest possible num
blsea [12.9K]

Answer:

\frac{11}{42} or 26.19%

Step-by-step explanation:

If the range of possible numbers is between 12 and 54 then that means that there are 42 (54 - 12) possible numbers that can be made. In this range, there are 11 prime numbers which are the following...

13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53

Therefore, the probability that the number formed is a prime would be \frac{11}{42} which if we divide and multiply the decimal by 100 we get the probability in percentage form.

\frac{11}{42} = 0.2619

0.2619 * 100 = 26.19%

Finally, we can see that the probability of this happening is 26.19%

3 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
Write and solve a real world problem involving the multiplication of a fraction and a whole number whose product is between 10 a
Fed [463]
A runner ran 1/2 of a mile for 24 days. How many miles did the runner run in all? (1/2×24=12) Therefore, the runner ran 12 miles in all in the course of 24 days.
4 0
3 years ago
Factorise x^2-x-6 please help
max2010maxim [7]

Answer:

Ask: Which two numbers add up to -1 and multiply to -6

-3 and  

2. Rewrite the expression using the above.

(x-3)(x+2)

Step-by-step explanation:

3 0
3 years ago
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