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3 years ago

Which of the binomials below is a factor of this trinomial?х2 - 10х- 39

Mathematics

1 answer:

bazaltina [42]3 years ago

7 0

Answer:

(x - 13) and (x + 3)

Step-by-step explanation:

Given

x² - 10x - 39

Consider the factors of the constant term (- 39) which sum to give the coefficient of the x- term (- 10)

The factors are - 13 and +3, since

- 13 × 3 = - 39 and - 13 + 3 = - 10, thus

x² - 10x - 39 = (x - 13)(x + 3) ← in factored form

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Find the critical value t a/2 needed to construct a confidence interval of the given level with the given sample size. level 95%

stepan [7]

Α = 1- (95/100) = 1-0.95 = 0.05

p = 1- α/2 = 1- 0.05/2 = 1-0.025 = 0.975

Degrees of freedom, df = Sample size -1 = 11-1 = 10

From t-tables, with cumulative probability pf 0.975 and df of 10,
Critical value = 2.228

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3 years ago

Help me please I don’t understand

Mamont248 [21]

For question between 13 -> 17 replace n with the number.

Example:
13.) n = 2; 2+(-1) = 1

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3 years ago

Order the given rational numbers from least to greatest: 4 1/4 3.3 3 1/3 -4 1/4 -3

spayn [35]

Answer:

-4 1/4 , -3 , 3.3, 3 1/3, 4 1/4

Step-by-step explanation:

make all fractions decimals

4 1/4 = 4.25

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-4 1/4 = -4.25

4.25 , -3 , 3.3 , 3.33... , 4.25

6 0

3 years ago

ILL GIVE 50 POINTS

Burka [1]

Answer:

Option 3 is right

Start at the origin. Move 3 and one-half units down because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between -3 and -4. Move 2 units right because the y-coordinate is -2.

Hope this helps:)

5 0

3 years ago

Read 2 more answers

Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

8 0

3 years ago

Which of the binomials below is a factor of this trinomial?х2 - 10х- 39​

Which of the binomials below is a factor of this trinomial?х2 - 10х- 39