You are correct! The problems that can arise with a function domain are:
In this case, you have a denominator, and you don't have roots nor logarithms. This means that your only concern must be the denominator, specifically, it cannot be zero.
And you simply have
So, the domain of this function includes every number except 3.
Answer: OPTION A.
Step-by-step explanation:
You can observe that in the figure CDEF the vertices are:
And in the figure C'D'E'F' the vertices are:
For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:
For C'(-8,-4) and C(-2,-1):
Let's choose another vertex. For E'(8,8) and E(2,2):
You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.
Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:
→
