Answer:
Step-by-step explanation:
In order to solve for this equation we have to note a couple of things.
There is a diagonal square inside a larger square. The space formed by the smaller square not being in the larger square is a right triangle.
The side length of the smaller square (4) is also the hypotenuse of this triangle.
Since we know that the other side length of the triangle is 3, we can use the Pythagorean Theorem to find the value of b.
The Pythagorean Theorem states that 
, where a and b are the legs and c is the hypotenuse.
We can substitute 3 in as a and 4 in as c and find b.
So b is 
units long.
Hope this helped!
Answer:
D In step 3
Step-by-step explanation:
Given polynomial: x² - 2x - 15 = 0
Step 1: factor the polynomial ⇒ (x + 3)(x - 5) = 0
Step 2: x + 3 = 0 and x - 5 = 0
Step 3: x = -3 and x = 5
x - 5 = 0
Add 5 to both sides:
⇒ x - 5 + 5 = 0 + 5
⇒ x = 5
Well there are 2 pecks in 1 kenning
So that's 2 × 1 peck = 1 kenning
2 kennings in 1 bushel
That's 2 × 1 kenning = 1 bushel
2 bushels in 1 strike
That's 2 × 1 bushel = 1 strike
4 strikes in 1 quarter
That's 4 × 1 strike = 1 quarter
4 quarters in 1 chaldron
That's 4 × 1 quarter = 1 chaldron
So now substitute again and again:
4 × 1 quarter = 1 chaldron
4 × ( 4 × 1 strikers ) = 1 chaldron
4 × ( 4 × ( 2 × 1 bushel ) ) = 1 chaldron
4 × ( 4 × ( 2 × ( 2 × 1 kenning ) ) ) = 1 chaldron
4 × ( 4 × ( 2 × ( 2 × ( 2 × 1 peck ) ) ) ) = 1 chaldron
4×4×2×2×2 peck = 1 chaldron
128 peck = 1 chaldron
So that's 128 × 1 peck = 1 chaldron.
Hope this helps.
Answer: A add the equations and C: Subtract the bottom equation from the top equation.
Step-by-step explanation: By adding the equations, you are left with
12x=8 which successfully eliminates the y values and subracting the bottom equation from the top equation.
Hope this helps! :)
