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3 years ago

6

A fort had enough provisions for 100 men for 8 days. If 60 more men were joined then how many days the provisions will last for?

1 answer:

Grace [21]3 years ago

8 0

Answer:

It would last for 3.2 days.

Step-by-step explanation:

100 men = 8 days

10 men = 0.8 days

60 men = 0.8 x 6 = 4.8 days

Now you subtract the days of 100 men and 60 men

8 - 4.8 = 3.2 days

Hope this helps!

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Given:

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To find:

The value of given expression by using the Laws of Exponents.

Solution:

We have,

$\left(-\dfrac{2}{3}\right)\times \left(-\dfrac{2}{3}\right)^3$

Using the Laws of Exponents, we get

$=\left(-\dfrac{2}{3}\right)^{1+3}$ $[\because a^ma^n=a^{m+n}]$

$=\left(\dfrac{-2}{3}\right)^{4}$

$=\dfrac{(-2)^4}{(3)^4}$ $[\because \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}]$

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$=\dfrac{16}{81}$

Therefore, the value of given expression is $\dfrac{16}{81}$ .

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Find the volume of this prism 41cm2 11cm

shusha [124]

Answer:

451 cm^3

Step-by-step explanation:

V = Bh (base area and height multiplied)

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3 years ago

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IgorC [24]

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An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

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The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

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$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

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From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

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Answer:

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Step-by-step explanation:

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