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Charra [1.4K]
3 years ago
12

The expansion of (x-2)(x+2) is …..​

Mathematics
2 answers:
den301095 [7]3 years ago
6 0

Answer:

  • (x+2)(x-2)
  • (x²-2²)
  • (x²-4)

hope it helps

<h2>stay safe healthy and happy...</h2>
KengaRu [80]3 years ago
3 0

Answer:

x2-4

Step-by-step explanation:

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What is the volume of the cylinder?
kvv77 [185]
For this case you can use the following equation:
 d = (2 2/5) h
 Rewriting:
 d = (2.4) h
 Then, we have that the height is:
 h = 22 1/4
 Rewriting:
 h = 22.25
 Finally the diameter is:
 d = (2.4) (22.25)
 d = 53.4 feet
 The volume of the cylinder is:
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 Nearest hundreth:
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6 0
3 years ago
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A basketball team needs to raise $500 and there are 12 players how much money does each player need to raise
Grace [21]

Answer:

$41.67

Step-by-step explanation:

Money that the team needs to raise $500

Players 12

Money ÷ Players = Money per player

500÷12=41.6666666666667

So... 41.67

Or if the question gave you description, follow that!

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According to the Venn diagram what type of parallelogram is both a rectangle and a rhombus
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A square can be both a rectangle and a rhombus
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In a pack of 52 cards, 4 of the cards are kings. the first card is picked, the results are recorded and the card is returned to
Ulleksa [173]
Total cards = 52

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8 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
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