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Charra [1.4K]
3 years ago
12

The expansion of (x-2)(x+2) is …..​

Mathematics
2 answers:
den301095 [7]3 years ago
6 0

Answer:

  • (x+2)(x-2)
  • (x²-2²)
  • (x²-4)

hope it helps

<h2>stay safe healthy and happy...</h2>
KengaRu [80]3 years ago
3 0

Answer:

x2-4

Step-by-step explanation:

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For each equation, determine whether it represents a direct variation, an inverse variation, or neither.
SSSSS [86.1K]

we know that in direct variation as x increase y also increases.

in indirect variation x decreases y increase and vice versa.

in part a we have x at top (numerator ) and y at denominator it mean indirect variation (as x increases y decreases).

to find k we know that for indirect variation xy=k

if we rewrite the equation x=9/y we get xy=9

which mean k=9 .

in part b we have 4xy=20 if we simplify this equation we get

xy=20/4=5

so here if we rewrite in terms of x.

we get x=5/y which represents indirect variation.

and we know xy=k

we have xy=5 .so k=5

8 0
3 years ago
Lim (sin(pi/x)) as x tends to 0 from both sides​
strojnjashka [21]

Hello from MrBillDoesMath!

Answer:

Limit does not exist.

Discussion:

The function 1/x has a vertical asymptote as x approaches 0 so

sin (pi/x) has no limit as x approaches 0. In fact, it oscillates wildly between -1 and 1 as x approaches 0. See attached graph of function

Thank you,

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8 0
3 years ago
Please help. Pythagorean theorem
zheka24 [161]

25 because the first square is a 3 by 3= 9 and the other one is 36 which is 6 by 6 and the last one is 4 by 4 so the last one is 5 by 5 or 25

6 0
3 years ago
Triangle ABC contains the point A(5,2). Find the coordinates of A' after a reflection over the x-axis
Sholpan [36]

Answer:

Step-by-step explanation:

Should be 5,-2 OR NOT

4 0
4 years ago
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
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