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2 years ago

18 – 12 + x = 10 What value of x makes the equation true? * explanation plz

Mathematics

2 answers:

Kay [80]2 years ago

7 0

Answer:

x = 4

Step-by-step explanation:

Solve for x:

x - 12 + 18 = 10

Hint: | Group like terms in x - 12 + 18.

Grouping like terms, x - 12 + 18 = x + (18 - 12):

x + (18 - 12) = 10

Hint: | Evaluate 18 - 12.

18 - 12 = 6:

x + 6 = 10

Hint: | Isolate terms with x to the left hand side.

Subtract 6 from both sides:

x + (6 - 6) = 10 - 6

Hint: | Look for the difference of two identical terms.

6 - 6 = 0:

x = 10 - 6

Hint: | Evaluate 10 - 6.

10 - 6 = 4:

Answer: x = 4

koban [17]2 years ago

3 0

Answer:

x = 4

Step-by-step explanation:

18 – 12 + x = 10

Combine like terms on the left side: 18 - 12 = 6

6 + x = 10

Subtract 6 from both sides.

x = 4

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3 years ago

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3 years ago

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BaLLatris [955]

Answer:

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2 years ago

How much material will Dmitri's mom need for the tent, including the floor?

suter [353]

<h3>Answer: 21.4 square meters</h3>

Work Shown:

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A = 2*1.7/2

A = 1.7

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L = (perimeter of the base)*(depth)

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2 years ago

Read 2 more answers

The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio

zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

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2 years ago