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lawyer [7]
3 years ago
8

18 – 12 + x = 10 What value of x makes the equation true? * explanation plz

Mathematics
2 answers:
Kay [80]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

Solve for x:

x - 12 + 18 = 10

Hint: | Group like terms in x - 12 + 18.

Grouping like terms, x - 12 + 18 = x + (18 - 12):

x + (18 - 12) = 10

Hint: | Evaluate 18 - 12.

18 - 12 = 6:

x + 6 = 10

Hint: | Isolate terms with x to the left hand side.

Subtract 6 from both sides:

x + (6 - 6) = 10 - 6

Hint: | Look for the difference of two identical terms.

6 - 6 = 0:

x = 10 - 6

Hint: | Evaluate 10 - 6.

10 - 6 = 4:

Answer: x = 4

koban [17]3 years ago
3 0

Answer:

x = 4

Step-by-step explanation:

18 – 12 + x = 10

Combine like terms on the left side: 18 - 12 = 6

6 + x = 10

Subtract 6 from both sides.

x = 4

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Out of a salary of $4500. I kept 1/3 as saving. Out of the remaining money. I spend 50% on food and 20% on house rent. How much
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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
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Answer:

x^4-3x^3+x^2-4

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C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

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Hey how do you get from standard form to vertex form?
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Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

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