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1 year ago

En una caja hay el doble de monedas que en otra. Si se pasan 7 monedas de la

1 answer:

8 0

De acuerdo con las ecuaciones lineales, la caja de mayor cantidad tuvo 28 monedas y la caja de menor cantidad tuvo 14 monedas.

<h3>Cuántas monedas hay en cada caja?</h3>

De acuerdo con el enunciado, existen dos cajas y una caja tiene el doble de monedas que la otra. Luego, se traslada 7 monedas a la caja de menor cantidad y se obtiene igual cantidad en ambas cajas. En consecuencia, la situación queda representada por la siguiente ecuación lineal:

2 · x - 7 = x + 7

(2 · x - x) - 7 = 7

2 · x - x = 7 + 7

(2 - 1) · x = 14

x = 14

La caja de menor cantidad tiene 14 monedas y la cantidad de monedas en la otra caja es:

y = 2 · x

y = 2 · 14

y = 28

La caja con mayor cantidad tiene 28 monedas.

Para aprender más sobre ecuaciones lineales: brainly.com/question/28371342

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2 years ago

Expand. (1-4m)(m^2-3m+8) your answer should be a polynomial in standard form.

sergiy2304 [10]

Answer:

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Step-by-step explanation:

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1 year ago

Radius of ball is 6in. What is the volume?

Lina20 [59]

Radius of ball is 6 inches. Then the volume is 904.32 $in^3$

<u>Solution:</u>

Given that, radius of a ball is 6 inches.

We have to find the volume of the ball with 6 inches radius.

Now, we know that, a ball will be in a shape of sphere, so we have to use the volume of a sphere formula to find the volume of the ball.

<em><u>The volume of sphere is given as:</u></em>

$\text { volume of sphere }=\frac{4}{3} \pi r^{3}$

where r is the radius.

Here in our problem, r = 6

$\text { Then, volume }=\frac{4}{3} \times \pi \times 6^{3}$

$\begin{array}{l}{=\frac{4}{3} \times \pi \times 6 \times 6 \times 6} \\\\ {=4 \times \pi \times 2 \times 6 \times 6} \\\\ {=8 \times \pi \times 36} \\\\ {=288 \pi=288 \times 3.14=904.32}\end{array}$

Hence the volume is 904.32 $in^3$

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3 years ago

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icang [17]

Answer:

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2 years ago

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Kobotan [32]

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3 years ago