Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
The statements are logically equivalent.
The 6th column is:
F T F F
The 7th column is:
F T F F
Step-by-step explanation:
The 6th column is just the opposite of the 5th column
The 7th column is T only if both the 1st and 4th are T
The correct answer is A, or x + 1 = 4x + 5. We used the substitution method to replace y with x + 1.
The third graph or bottom left graph represents 
Step-by-step explanation:
Step 1:
To determine which of the given graphs represents the equation 
, we substitute some values in the place of x.
When 
Anything with an exponent of 0 will equal 1.
So the graphs on the right side cannot be the answers.
Step 2:
Now we substitute another value to determine which graph represents
When 
The value of f(x) when 
is lesser than the value of f(x) when 
So the third graph or bottom left graph represents
