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3 years ago

14

The rectangle below has an area of x^2-4x-12 square meters and a length of x + 2 meters. Which represents the width of the recta

ngle ?

1 answer:

zaharov [31]3 years ago

7 0

The answer is 7.-2 I just did this question

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10-11d>-5d-4 show step by step

aliya0001 [1]

The first step for solving this is to move the variable to the left side and then change its sign.
10 - 11d + 5d > - 4
Now move the constant to the right side and change its sign.
-11d + 5d > -4 - 10
Collect the terms with a d variable.
-6d > -4 - 10
Calculate the difference on the right side.
-6d > -14
Lastly,, divide both sides of the inequality by -6 and flip the inequality sign to find your final answer.
d < $\frac{7}{3}$
Let me know if you have any further questions.
:)

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3 years ago

Georgia, a florist, charges 10.95 per flower bundle plus a 15 delivery charge per order. If Charlie orders 8 bundles of flowers

Ivan

Georgia charges Charlie $102.60 in total.

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3 years ago

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SPAM IN THE QUESTION COMMENTS free points to :)

Semenov [28]

Answer:

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Step-by-step explanation:

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3 years ago

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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

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2 years ago

(2x2 - 4x + 7) + (3x3 - 9x)

Leviafan [203]

The answer is 20-13x

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