Answer:
A = (x + 15)(x + 10) − 5
Step-by-step explanation:
(x+15)(x+10)-5=A would be a solution
To make this easier, let's assign x a value. Let's say 3.
(3+15)(3+10)-5=A
(18)(13)-5=A
234-5=A
A=229
Now with this, we put x in the answer choice and the answer that gives an area of 229 is correct.
A. A=(3+20)(3+10)+12=(23)(13)+12=299+12=311 <u>Answer A is wrong.</u>
B. A=(3+20)(3+10)-12=(23)(13)-12=299-12=287 <u>Answer B is wrong.</u>
C. A=(3+26)(3+15)=(29)(18)=522 <u>Answer C is wrong.</u>
D. A=(3+14)(3+8)=(17)(11)=187 <u>Answer D is wrong.</u>
It's either I'm wrong or the answer choices are wrong.
New answer choices!
A. A=(3+20)(3+11)
=(23)(14)=322 Answer A is wrong.
B. A=(3+15)(3+10)+5
=(18)(13)+5=234+5=239 Answer B is wrong.
C. A=(3+15)(3+10)−5
=(18)(13)-5=234-5=229 Answer C is correct.
D. A=(3+9)(3+10)=(12)(13)=156 <u>Answer D is wrong.</u>
Weight of other bag would be 14/15 kg
Answer:
Step-by-step explanation:
Suppose we think of an alphabet X to be the Event of the evidence.
Also, if Y be the Event of cheating; &
Y' be the Event of not involved in cheating
From the given information:
Thus, 
P(Y') = 1 - 0.01
P(Y') = 0.99
The probability of cheating & the evidence is present is = P(YX)
The probabilities of not involved in cheating & the evidence are present is:
(b)
The required probability that the evidence is present is:
P(YX or Y'X) = 0.006 + 0.000099
P(YX or Y'X) = 0.006099
(c)
The required probability that (S) cheat provided the evidence being present is:
Using Bayes Theorem
<span>1. First, label the axis on your graph, with units:
time on the x-axis, in units of hours;
distance on the y-axis, in units of miles.
2. Draw a graph of distance vs. time. Distance after the first hour = 69 miles, distance after the 2nd hour = 138 miles, etc.
3. Observe that this graph is a STRAIGHT LINE with constant slope. Therefore the relationship is PROPORTIONAL.
For every other kind of graph -- i.e. not a straight line -- the relationship is NON-PROPORTIONAL.
Hope this helps. </span>
