3 years ago

What fractional part of a pound is an ounce

1 answer:

6 0

<span>That depends on what you mean by "pound" and "ounce."

There are 16 English ounces in an English pound. There are 12 troy ounces in a troy pound.</span>

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What is the value of v in the equation?<br> V - 7 = 15 + 12<br><br> A.21<br> B.13<br> C.27<br> D.34

Serjik [45]

Answer:

D. 34

Step-by-step explanation:

15+12=27

v-7=27

+7. +7

______

v=34

3 0

2 years ago

Can anyone solve this for me?<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a

stellarik [79]

Answer: 9x - 485/81

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3 years ago

Simplify 4x + 5×-5y+3y

uysha [10]

$4x+5x-5y+3y
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2 years ago

Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the <u>area of a trapezoid </u>is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

5 0

3 years ago

What is the length of the second base of a trapezoid if the length of one base is 24 and the length of the mid segment is 19

rodikova [14]

The sum of the two bases is twice the length of the mid segment
24+x=19*2
x=14

6 0

3 years ago