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topjm [15]
3 years ago
15

What fractional part of a pound is an ounce

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

<span>That depends on what you mean by "pound" and "ounce."

There are 16 English ounces in an English pound. There are 12 troy ounces in a troy pound.</span>

<span>
</span>
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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
The parallelogram shown represents a map of the boundaries of a natural preserve. Walking trails run from points A to C and from
Citrus2011 [14]

y+2 = 3y-4 =

y+6 = 3y

6 =2y

y = 3


y+2 = 3+2 = 5

3y-4 = 3(3)-4 = 5

 5+5 =10


2y-3 = 2(3) - 3 = 3

3+3 = 6


10+6 = 16 miles

answer is C

4 0
3 years ago
Read 2 more answers
I need help on 19 and 20. Please help me. Please don’t put a link. Please help me.
lianna [129]

Answer:

19:

4  <   third side    <   14  

20:

3  <   third side    <   13  

Step-by-step explanation:

hint: go to http://www.17 28.org/trianinq.htm

(fix the space between 17 and 28)

you're welcome xx

6 0
2 years ago
sneakers are on sale for 80% off their original price. in addition, jade has a coupon that gives her 15% discount off the sale p
iris [78.8K]
<span>122.40 is the answer. I hope this helps :) Please give me a rate and Thanks :)</span>
4 0
3 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
aleksley [76]

The length of PR is 4.4 units.

Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

\cos \theta=\frac{a d j}{h y p}

Here,  \theta=64, adj = PR and hyp = 10

Substituting these values in the formula, we get,

\cos 64=\frac{P R}{10}

Multiplying both sides by 10, we get,

10*\cos 64={P R}

Substituting the value for cos 64, we get,

10*0.438={P R}

Multiplying, we have,

4.38=PR

Rounding off, we get,

PR=4.4

Thus, the length of PR is 4.4 units.

8 0
3 years ago
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