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castortr0y [4]
3 years ago
7

One six-sided die and one sixteen-sided die are rolled. What is the probability of rolling an even number on the six-sided die a

nd rolling a 16 on the other die?
0.031
0.167
0.229
0.063
Mathematics
2 answers:
RSB [31]3 years ago
5 0

You have a 3/6 chance of getting even number (there are 3 even nunbers in the 6 die)

You have a 1/16 chance of getting a 16 on the other die

multiply them 1/3 × 1/16 then convert it to decimal form is your answer

zalisa [80]3 years ago
4 0

Answer:

0.031

Step-by-step explanation:

you have a 1/2 chance of rolling an even number and a 1/16 chance of rolling 16. when you multiply 1/2 by 1/16 you get 1/32 and after converting that to decimal you are left with: 0.031

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Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable
bekas [8.4K]

Answer:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

u=\frac{y}{x}

Multiply both sides by x:

ux=y

Second step: Differentiate the substitution:

u'x+u=y'

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}

u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of x^2 so I'm going to divide top and bottom by x^2:

u'x+u=\frac{u+u^2}{3+u^2}

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

u'x=\frac{u+u^2}{3+u^2}-u

Find a common denominator: Multiply second term on right hand side by \frac{3+u^2}{3+u^2}:

u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}

Combine fractions while also distributing u to terms in ( ):

u'x=\frac{u+u^2-3u-u^3}{3+u^2}

u'x=\frac{-u^3+u^2-2u}{3+u^2}

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

u' \frac{3+u^2}{-u^3+u^2-2u}x=1

Divide both sides by x:

\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}

Reorder the top a little of left hand side using the commutative property for addition:

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The expression on left hand side almost matches your expression but not quite so something seems a little off.

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