Question

Determine the equation of a line passing through (2,1) and perpendicular to the line containing points (2-2) and (4,10)

Answer 1

(2,-2)(4,10)
slope = (10 - (-2) / (4 - 2) = (10 + 2) / 2 = 12/2 = 6
The slope of the original equation is 6, but we are looking for a perpendicular line, so we need the negative reciprocal slope. All that means is " flip " the slope and change the sign. 6 or 6/1.....flip it...1/6...change the sign....-1/6. So we will need the slope of -1/6.

y = mx + b
slope(m) = -1/6
(2,1)...x = 2 and y = 1
now we sub and find b, the y intercept
1 = -1/6(2) + b
1 = -1/3 + b
1 + 1/3 = b
3/3 + 1/3 = b
4/3 = b

so ur perpendicular equation is : y = -1/6x + 4/3