A sequence is given by the rule 4n – 5

1 answer:

4 0

What you can do: (n)a=(n)(4+1/n)
Know divide away each n on respective side you get:
a=4+1/n
Know when n=0, 1/0 is not defined there’s that
n=1 , 4+1/1 = 5
n=2 , 4+1/2 = 4.5
n=3 , 4.33
n=4, 4.25

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If sinA+cosecA=3 find the value of sin2A+cosec2A

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Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

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$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used: