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nordsb [41]
3 years ago
13

Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartF

raction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction x = 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartFraction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction . In which step did he use the addition property of equality?

Mathematics
2 answers:
Archy [21]3 years ago
6 0

Answer:

step 2

Step-by-step

the other guy said it.

Ghella [55]3 years ago
3 0

Rahul use addition property of equality in step 2.

Solution:

The image of the question is attached below.

Step 1:

$2 x-\frac{1}{4}-\frac{3}{5} x=\frac{55}{4}

combine like terms together.

$2 x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}

To make the denominator same multiply and divide 2x by 5.

$\frac{10}{5} x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}  

Step 2:

$\frac{7}{5} x-\frac{1}{4}=\frac{55}{4}

By addition property of equality, add \frac{1}{4} on both side of the equation.

$\frac{7}{5} x-\frac{1}{4}+\frac{1}{4}=\frac{55}{4}+\frac{1}{4}

Step 3:

$ \frac{7}{5} x=\frac{56}{4}

Step 4:

Multiply by \frac{5}{7} on both side of the equation.

x=10

Hence Rahul use addition property of equality in step 2.

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<h3>Method used for diagram and for the distance calculation</h3>

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