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2 years ago

What is the domain of the function f(x) = (-5/6)(3/5)superscript x

Mathematics

1 answer:

Georgia [21]2 years ago

5 0

Answer:

$-\infty < x < \infty$

Step-by-step explanation:

Given

$f(x) = (-\frac{5}{6}) \cdot (\frac{3}{5})^x$

Required

The domain

There are no undefined points such as denominator of x or square roots.

Hence, the domain is:

$-\infty < x < \infty$

You might be interested in

Apply the Pythagorean Theorem to find the distance between points A and B.

irinina [24]

Answer:

Properties of a right tangle can be created in a Coordinate Plane

Distance between two points A and B are shown as below

Step-by-step explanation:

Find distance between two point using Pythagorean Theorem.

Properties of right triangles and creating right triangle as a coordinate Plane.

Suppose two point are drawn in triangle containing value of (-2 , 4 ) and (-2, -2)

then

In (-2 , 4 ) and (-2,-2)

taking y-values that is 4 and -2

find difference between them such as

4-(-2) = 6

Distance is (-2,4) is 6 unit from (-2,-2)

We can also find unit length of A and B

Side A: (-1, 2) and (3,2)

3-(-2) = 5

side A is 5 unit in length

Side B : (-2,2) and (-2,-1)

2 - (-1) = 3

Side B is 3 unit in length

7 0

3 years ago

Read 2 more answers

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$