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2 years ago

5

Someone please help I’ve asked like everyone I know, and I don’t remember learning this in class either, I’ll give brainliest ❤️

❤️❤️

2 answers:

max2010maxim [7]2 years ago

8 0

3.24x10^26 , have a nice day :)

dsp732 years ago

4 0

Answer:

I think it would be 3.24x10^26

Step-by-step explanation:

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Emanuel has 12 trading cards and then buys some more cards at the store. His aunt joan him a package of six cards for his birthd

sveta [45]

A) the equation accuretly models this scenario because Emanuel has a total of 48 cards. He bought some (X) and his aunt gave him 18. In order to find the number of cards he bought you set the number of cards he bought and the number of cards he got from his aunt equal to the number of cards he has. B) 48= X + 18 Subtract 18 over 30=X He bought 30 cards from the store. 48+ 30+18

7 0

2 years ago

Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf

Papessa [141]

The table is missing in the question. The table is provided here :

Group 1 Group 2

34.86 64.14 mean

21.99 20.46 standard deviation

7 7 n

Solution :

a). The IV or independent variable = Group 1

The DV or the dependent variable = Group 2

b).

$H_0: \mu_1 = \mu_2$

$H_a:\mu_1 < \mu_2$

Therefore, $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now, $df = min(n_1 - 1, n_2 - 1)$

df = 7 - 1

= 6

Therefore the value of p :

$=T.DIST(-2.579143,6,TRUE)$

= 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0

3 years ago

What is the value of p+9 when p=16

Tasya [4]

Answer:

25 :)

Step-by-step explanation:

well, if it's p+9 and you know that p=16 then you plug 16 in for p so the equation will be 16+9 and then you solve from there which is 25

4 0

2 years ago

Помогите математика !!!!!!

ohaa [14]

Answer:

sorry say nice its out of understand

4 0

2 years ago

T F IfA and B are similar matrices, then AT=BT

muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices $A$ and $B$ exists an invertible matrix $P$ for which

$[tex]B = P^{-1} AP$ [/tex]

∴ $B^{T} = (P^{-1})^{T} A^{T} P^{T} \\$

Also $P^{-1}P = I\\$

and $(P^{-1})^{T} = (P^{T})^{-1}$

∴ $(P^{-1})^{T}P^{T} = I$

so, $B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}$

7 0

3 years ago