Answer:
54 units squared
Step-by-step explanation:
You have to divide the shape into simpler shapes such as rectangles and triangles that you can easily find the area of. Then, add those areas together. I divided it into one rectangle and three triangles.
Rectangle 1: length=7 width=6 6(7)=42
Triangle 1: base=6 height=2 1/2(6)2=6
Triangle 2: base=3 height=2 1/2(3)2=3
Triangle 3: base=6 height=1 1/2(6)1=3
Area= R1+T1+T2+T3= 42+6+3+3= 54 units squared
Answer:
x= 1 , y=4
Step-by-step explanation:
x-y= -3 => Equation 1
x+5y= 21 => Equation 2
<u>Substitut</u><u>ion</u><u> </u><u>Method</u><u>:</u>
<u>Substitu</u><u>te</u><u> </u><u>Equation</u><u> </u><u>1</u>=>
x=y-3 <= Equation 3
Put x=y-3 in Equation 2:
x+5y=21
( y-3)+5y=21
y-3+5y=21
6y-3=21
6y=21+3
6y=24
y=24÷6
y=4
Put y=4 in Equation 1:
x-y= -3
x-4=-3
x=4-3
x=1
Hope this helps :)
Answer:
f(x) = 12x - 4
Step-by-step explanation:
f(x)= 20 + 12(x - 2)
Distribute
f(x) =20 +12x - 24
Combine like terms
f(x) = 12x+20-24
f(x) = 12x - 4
Answer:12/1
Step-by-step explanation:
Answer:
The correct order is:
a
c
d
b
Step-by-step explanation:
First, let's write 1/x in a convenient way for us:
a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.
Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:
c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.
Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:
d) Observe that x is the quotient of two integers with the denominator nonzero.
And that is the definition of rational, then we end with:
b) Hence x is rational.
Which is what we wanted to get.
