Find an equation for the nth term of the sequence. -4, -16, -64, -256, ...

Mathematics

2 answers:

Hoochie [10]2 years ago

7 0

Common ratio = 4
Starts at -4

So the equation is n = -4 *4^(n-1)

Andrews [41]2 years ago

5 0

This is a geometric sequence with first term a1 = -4 and common ratio r = 4

so nth term = a1* r^(n-1)

= -4 *4^(n-1)

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What is an equation of the line that passes through the points (0, -7) and (-8, 3)?

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Answer <u>(assuming it can be in slope-intercept form)</u>:

$y = -\frac{5}{4} x-7$

Step-by-step explanation:

1) First, find the slope of the line by using the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(3)-(-7)}{(-8)-(0)}\\m = \frac{3+7}{-8-0} \\m = \frac{10}{-8} \\m = -\frac{5}{4}$

So, the slope is $-\frac{5}{4}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. Substitute real values for the $m$ , $x_1$ , and $y_1$ in the formula.

Since $m$ represents the slope, substitute $-\frac{5}{4}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point the line intersects, choose any one of the given points (either one is fine, it will equal the same thing at the end) and substitute its x and y values into the formula as well. (I chose (0, -7), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the following answer:

$y-(-7) = -\frac{5}{4} (x-(0))\\y + 7 = -\frac{5}{4} x\\y = -\frac{5}{4} x-7$