answer
10
step-by-step explanation
the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7
substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)
sin(x) = cos(y)
sin(2k + 3) = cos(6k + 7)
we know that sin(x) = cos(90 -x)
sin(2k + 3)
= cos(90 - (2k + 3) )
= cos(90 - 2k - 3)
= cos(87 - 2k)
substitute this into the equation sin(2k + 3) = cos(6k + 7)
sin(2k + 3) = cos(6k + 7)
cos(87 - 2k) = cos(6k + 7)
87 - 2k = 6k +7
80 = 8k
k = 10
It's just asking for the gradient basically
150/3 = 50
Or technically -50 because it's decreasing
Answer:
Neither the ranges nor the interquartile ranges for the data sets are the same.
Step-by-step explanation:
In a visual display, the boxplot presents five sample statistics: the minimum, the lower quartile, the median, the upper quartile and the maximum, and the box length gives an indication of the sample variability and the line across the box shows where the sample is centred, with an end at each quartile. The length of the box is thus the interquartile range of the sample and, whether the sample is symmetric or skewed, either to the right or left, the "shape" of the sample, and by implication, the shape of the population from which it was drawn, considering appropriate analyses of the data.
(x-3.2, y+1) . Y'=(4.3, 6) Z'=(4.8, 5)
The preimage (6,-2.3) differs from the image (2.8,-1.3) by subtracting the coordinates of the pre-image from the image leaving a -3.2 difference for x and a +1 for the y value. apply this rule to Y and Z to get Y' and Z'.
