Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Answer:
Step-by-step explanation:
The opposite side to angle B is 4. It is the line AC. AC is not connected in any way to <B
The adjacent side is one of the two sides making up <B. It is 3.
Tan(B) = opposite / adjacent
Tan(B) = 4/3
<B = tan-1(4/3)
<B = 53.13
Answer:
10 because there there are 2 ten
B C and E have a unit rate of 12 yards or second
Answer:
I think I got it right! I think it's x=4
if not I'm sorry :(
