Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
Answer:
1 / 4 ton will cover 1 square yard
Step-by-step explanation:
(3 / 4) / 3 =
3 / 4 x 1 / 3 =
3 / 12 =
1/4 ton
BRYAN would need to buy 3 gallons and 8 quarts witch would cost
$14.99 times 3 and $4.99 times 8
$44,97+$39.92=$84.98 would be spent for all off the paint he needs
The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
Step-by-step explanation:
The given is,
Given diagram is combination of Rectangle and Semi circle.
Step:1
Res the attachment,
Area of given diagram = Area of A + Area of B..............(1)
Step:2
For A,
The A section in the given diagram is semi circle,
Diameter of semi circle = Total distance - ( 2+3)
( ∵ 2, 3 are top distance in the given diagram)

Diameter, d = 5 cm
Radius, 

r = 2.5 cm
Area,
........................(2)


Step:3
For B,
Area of rectangle is,
.....................(3)
Where, l - Length = 10 cm
b - Width = 2 cm
Equation (3) become,


Area of B,
= 20 
Step:4
From the equation (1),
Area of given diagram = 20+ 9.81747
Area = 29.817 square centimeters
Result:
The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
Answer:

Step-by-step explanation:
Let sides of the triangle be 

Semi-perimeter (s) = 

Area of one tile 

So,
Area of 20 tiles 
Cost of polishing the floor at the rate of 2 rupees per sq.cm = 