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gogolik [260]
3 years ago
14

Help please ASAP quickly

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Ok so I created a equation to see how many seconds can you go to get to 180. The equation is 0.4x = 180 and I got 450. Now I concluded from this result the inequality is A, x < 450 because unless you want your submarine to crash in the seafloor you should probably stop before 450 seconds.

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The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime
Aleks [24]

Answer:

64√2 or 64 StartRoot 2 EndRoot

Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

X=(128√2)/2= 64√2 cm.

Since X is the leg, the answer would be 64√2

3 0
2 years ago
Read 2 more answers
Solve by using factorizing method:4x²-36x+81=0​
boyakko [2]

Answer:

  • x = 4.5

Step-by-step explanation:

  • 4x² - 36x + 81 = 0​
  • (2x)² - 2*2x*9 + 9² = 0           Identity  a² - 2ab + b² = (a - b)²
  • (2x - 9)² = 0
  • 2x - 9 = 0
  • 2x = 9
  • x = 4.5

8 0
2 years ago
How do I write these ratios 10/20 and 2/2 in y=kx form
hodyreva [135]
You would write it 2=10(20+2)
6 0
3 years ago
What can you say about the y-values of the two functions f(x)=-5^x +2 and g(x)=-5x^2+2?
Kryger [21]

Answer:

B) The maximum y-value of f(x) approaches 2

C) g(x) has the largest possible y-value

Step-by-step explanation:

f(x)=-5^x+2

f(x) is an exponential function.

Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞

Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→

Lim x→ -∞ f(x) = 2

Then the maximun y-value of f(x) approaches 2


g(x)=-5x^2+2

g(x) is a quadratic function. The graph is a parabola

g(x)=ax^2+bx+c

a=-5<0, the parabola opens downward and has a maximum value at

x=-b/(2a)

b=0

c=2

x=-0/2(-5)

x=0/10

x=0

The maximum value is at x=0:

g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2

The maximum value of g(x) is 2

7 0
3 years ago
Solve for x: sinx-cosx=√2
kvv77 [185]
<span>sinx - cosx =sqrt(2)
Taking square on both sides:
</span>(sinx - cosx)^2 =sqrt(2)^2<span>
sin^2(x) -2cos(x)sin(x) + cos^2(x) = 2
Rearranging the equation:
sin^2(x)+cos^2(x) -2cos(x)sin(x)=2
As,
</span><span>sin^2(x)+cos^2(x) = 1
</span><span>So,
1-2sinxcosx=2
 1-1-2sinxcosx=2-1
 -</span><span>2sinxcosx = 1
</span><span>Using Trignometric identities:
-2(0.5(sin(x+x)+sin(x-x))=1 
-sin2x+sin0=1
As,
sin 0 = 0
So,
sin2x+0 = -1
</span><span>sin2x = -1</span><span>
2x=-90 degrees + t360
Dividing by 2 on both sides:
x=-45 degrees + t180
or 2x=270 degrees +t360
x= 135 degrees + t180 where t is integer</span>
6 0
3 years ago
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