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love history [14]
3 years ago
11

The bus fare in a city is People who use the bus have the option of purchasing a monthly coupon book for With the coupon​ book,

the fare is reduced to​ $0.50. How many times must someone use the bus so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon​ book? Express the total monthly cost to use the bus with a coupon​ book, f, as a function of the number of times in the month the bus is​ used, x. Then express the total monthly cost to use the bus without a coupon​ book, g, as a function of the number of times in the month the bus is​ used, x.
Mathematics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

26 times

Step-by-step explanation:

The question has missing details. However, the given parameters are

Given

Without Coupon

Bus Fare = $2.00

With Coupon

Coupon = $39.00

Bus Fare = $0.50

Represent the number of fares with x

Without Coupon, cost of fares is

Cost = 2x

i.e.

f(x) = 2x

With Coupon, cost of fares is

Cost = 39 + 0.5x

i.e.

g(x) = 39 + 0.5x

To calculate when both fares will be equal, we must have:

f(x) = g(x)

2x = 39 + 0.5x

Collect like terms

2x - 0.5x = 39

1.5x = 39

Solve for x

x = 39/1.5

x = 26

This implies that, for both cost to be equal, the person must go 26 times

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Answer:

X= 24

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    3/4*x-(18)=0

Step by step solution :

Step  1  :

           3

Simplify   —

           4

Equation at the end of step  1  :

  3        

 (— • x) -  18  = 0

  4        

Step  2  :

Rewriting the whole as an Equivalent Fraction :

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         18     18 • 4

   18 =  ——  =  ——————

         1        4  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

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—————————————  =  ———————

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Pulling out like terms :

3.1     Pull out like factors :

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Equation at the end of step  3  :

 3 • (x - 24)

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Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

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Here's how:

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    4    

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The equation now takes the shape :

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Equations which are never true :

4.2      Solve :    3   =  0

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Solving a Single Variable Equation :

4.3      Solve  :    x-24 = 0

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t N.

In the figure shown below

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