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4 years ago

What is the equation of the line on the graph with points (-2,2) and (-2,-3)

Mathematics

1 answer:

nika2105 [10]4 years ago

4 0

Answer:

x=-2

Step-by-step explanation:

Given points are (-2,2) and (-2,-3).

Now we need to find equation of the line passing through the given points.

So let's begin by finding slope

$m=\frac{\left(y_2-y_1\right)}{\left(x_2-x_1\right)}=\frac{\left(-3-2\right)}{\left(-2-\left(-2\right)\right)}=\frac{\left(-5\right)}{\left(-2+2\right)}=-\frac{5}{0}$

which is undefined. That means graph of the line must be vertical as you can see that in given points, x-value is not changing.

Equation of vertical line is given by x=k where k is the fixed value of x-coordinate.

x-coordinate is -2 in given points.

Hence final equation is x=-2.

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1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

3 years ago

Sammy counts the number of people in one section of the school auditorium. He counts 18 female students, 16 male students, and 6

Rzqust [24]

Correct Question:

He counts 18 female students, 16 male students, and 6 teachers. There are

720 people in the auditorium. Consider the probability of selecting one person

at random from the auditorium.

Which of these statements are true?

Choose all that apply.

A: The probability of selecting a teacher is 6%.

B : The probability of selecting a student is 85%.

C : The probability of selecting a male student is 32%.

D : The probability of selecting a female student is 45%.

Step-by-step explanation:

Option B and D are correct because

The total number of people in one cross section = 18 + 16 + 6 = 40.

A = The probability of selecting a teacher is = (6/40)x100 = 15 % not equal to 6 %

B = The probability of selecting a male student is = (34/40)x100 = 85%

C = The probability of selecting a male student is = (16/40)x100 = 40 % not equal to 32 %

D : The probability of selecting a female student is = (18/40)x100= 45%

3 0

3 years ago

Please help I don't understand exponents

Mkey [24]

Answer:

1.) the answer is the fourth one, 1/5^7

2.) the answer is the fourth one, 1/5^6

3.) the answer is the fourth one, (2^6)^-5

4.) this is seems to be a duplicate of the first one

Step-by-step explanation:

1.) by 'adding' 4 exponent values on the top it simplifies the top to simply one and 5^7 on the bottom

2.) since this is an exponent of an exponent multiply them, getting 5^-6, then simplify negative exponents.

3.) exponents of exponents are multiplied

4 0

3 years ago

Read 2 more answers

I dont understand how to do the 2x part.

kodGreya [7K]

Answer:

x=6 2/3

Step-by-step explanation:

Ratio of DEF:ABC=5/3

8*5/3=13 1/3

x=6 2/3

4 0

3 years ago

If you roll a standard 6 sided die, whats the probability that you get a 1,2,3,5, or 6?

Papessa [141]

Answer:

5/6

Step-by-step explanation:

1 has a 1/6 chance
2 has a 1/6 chance
3 has a 1/6 chance
5 has a 1/6 chance
6 has a 1/6 chance
1, 2, 3, 5, or 6 has a 1/6+1/6+1/6+1/6+1/6=5/6 chance

6 0

3 years ago

Read 2 more answers